16x=2x^2+30

Solution for 16x=2x^2+30 equation:

16x=2x^2+30

We move all terms to the left:

16x-(2x^2+30)=0

We get rid of parentheses

-2x^2+16x-30=0

a = -2; b = 16; c = -30;
Δ = b2-4ac
Δ = 162-4·(-2)·(-30)
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4}{2*-2}=\frac{-20}{-4}
=+5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4}{2*-2}=\frac{-12}{-4}
=+3
$